basictypes: StraightLine:

- Fix return type hint for __find_line()
	- Rename Line to StraightLine
	- Getters for m and b in StraightLine
	- intercept in StraightLine
		Find the intercept point of 2 Striaght lines

Signed-off-by: HeshamTB <hishaminv@gmail.com>

basictypes.py

@@ -51,7 +51,7 @@ class PointWithID(Point):
     def get_wallid(self):
         return self._wall_id
 
-class Line:
+class StraightLine:
 
     IDX_M = 0
     IDX_B = 1
@@ -63,7 +63,7 @@ class Line:
         if not self.__matching_wall_ids(p1, p2): 
             raise WallIDMismatch('Wall ID for points does not match')
 
-    def __find_line(self, p1:PointWithID, p2:PointWithID) -> float:
+    def __find_line(self, p1:PointWithID, p2:PointWithID) -> tuple:
         m = (p2.get_y() - p1.get_y()) / (p2.get_x() - p1.get_x())
         # Using p1 to find b
         b = p1.get_y() - (m*p1.get_x())
@@ -74,6 +74,28 @@ class Line:
     def __matching_wall_ids(self, p1, p2) -> bool:
         if p1.get_wallid() == p2.get_wallid(): return True
         return False
+    
+    def get_m(self)-> float:
+        return self.m
+    
+    def get_b(self) -> float:
+        return self.b
+
+    def get_wall_id(self) -> str:
+        return self.wall_id
+
+    def intercept(self, line) -> Point:
+        # Basically when the two lines have the same cords (x,y)
+        # As a formula x = (b2 - b1)/ (m1 + m2) to find X, then apply y = mx + b on any line
+        x = (line.get_b() - self.get_b()) / (line.get_m() + line.get_m())
+        y = self.get_m()*x + self.get_b() # Inline to reduce overhead
+        return Point(x, y)
+
+    def intercept_list(self, lines) -> list:
+        # May return a sorted list based on distance
+        # Consider vectorized (SIMD) implmentaion with numpy
+        pass
+
 
 class WallIDMismatch (RuntimeError): ...