b036453851
Simple web interface using the API should be mobile compatible. A simple GUI interface using the original python script as the basis.
65 lines
2.1 KiB
Python
65 lines
2.1 KiB
Python
#!/usr/bin/env python
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from tkinter import Tk, Label, Button, Entry, StringVar, IntVar, END, W, E
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from pwned import lookup_pwned_api
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import hashlib
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import sys
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try:
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import requests
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except ModuleNotFoundError:
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print("### pip install requests ###")
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raise
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class Calculator:
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def __init__(self, master):
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self.master = master
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master.title("pwned GUI by PPC")
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self.p = "";
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self.head_label_text = ""
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self.head_label = Label(master, textvariable=self.head_label_text)
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self.label = Label(master, text="Enter the password to check : ")
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vcmd = master.register(self.validate) # we have to wrap the command
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self.entry = Entry(master, validate="key", validatecommand=(vcmd, '%P'))
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self.submit_button = Button(master, text="Check", command=lambda: self.update("submit"))
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self.total_label_text = "Number of times Password found : ...."
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self.total_text = StringVar()
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self.total_text.set(self.total_label_text)
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self.total_label = Label(master, textvariable=self.total_text)
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self.total = Label(master, text="")
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# LAYOUT
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self.label.grid(row=0, column=0, sticky=W, padx=(25, 25), pady=(25, 10))
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self.head_label.grid(row=0, column=1, columnspan=4, sticky=E, padx=(25, 25), pady=(10, 10))
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self.entry.grid(row=2, column=0, columnspan=3, sticky=W+E, padx=(25, 25), pady=(10, 10))
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self.submit_button.grid(row=2, column=4, sticky=W+E, padx=(25, 25), pady=(10, 10))
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self.total_label.grid(row=4, column=0, columnspan=3, sticky=W, padx=(25, 25), pady=(10, 20))
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def validate(self, new_text):
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if not new_text: # the field is being cleared
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return True
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try:
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self.p = new_text
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return True
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except ValueError:
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return False
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def update(self, method):
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self.total = "Number of times Password found : " + str(lookup_pwned_api(self.p)[1])
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self.total_text.set(self.total)
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self.entry.delete(0, END)
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root = Tk()
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my_gui = Calculator(root)
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root.mainloop() |